If 25.0 g of NaCl is dissolved to prepare 0.500 L of solution, what is the molarity?

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Multiple Choice

If 25.0 g of NaCl is dissolved to prepare 0.500 L of solution, what is the molarity?

Explanation:
Molarity is the amount of solute in moles per liter of solution. Convert the mass of NaCl to moles using its molar mass (58.44 g/mol): 25.0 g × (1 mol / 58.44 g) ≈ 0.428 mol. The total solution volume is 0.500 L, so the molarity is 0.428 mol / 0.500 L ≈ 0.856 M. The correct result is about 0.856 M; none of the given options matches this value, indicating a possible error in the listed choices. The key steps are turning mass into moles with the molar mass and then dividing by the final volume.

Molarity is the amount of solute in moles per liter of solution. Convert the mass of NaCl to moles using its molar mass (58.44 g/mol): 25.0 g × (1 mol / 58.44 g) ≈ 0.428 mol. The total solution volume is 0.500 L, so the molarity is 0.428 mol / 0.500 L ≈ 0.856 M. The correct result is about 0.856 M; none of the given options matches this value, indicating a possible error in the listed choices. The key steps are turning mass into moles with the molar mass and then dividing by the final volume.

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